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2.5^2+6^2=x^2
We move all terms to the left:
2.5^2+6^2-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+42.25=0
a = -1; b = 0; c = +42.25;
Δ = b2-4ac
Δ = 02-4·(-1)·42.25
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-13}{2*-1}=\frac{-13}{-2} =6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+13}{2*-1}=\frac{13}{-2} =-6+1/2 $
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